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Location of a Centroid

  • Thread starter WRX200
  • Start date
  • #1
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I'm at a complete loss on this one, so far. This problem needs to be solved symbolically with Matalb (which won't be a problem once I know what to do), but I'm not even sure where to begin. Any help would be greatly appreciated

[PLAIN]http://img227.imageshack.us/img227/9344/prob18.jpg [Broken]
 
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Answers and Replies

  • #2
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Due to symmetry of the function xc = b/2. To find xc, just evaluate the two integrals. Are you having trouble setting them up?
 
  • #3
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Yes, I'm unsure how to manipulate the other functions in order to relate everything. I just seem to be completely missing something
 
  • #4
33,169
4,853
That's pretty vague. You need to evaluate two integrals. What do you have for them?
 
  • #5
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I was just being dumb, looking at the problem the wrong way. I was trying to relate yc and y, and I wasn't considering how y and dx were factoring into dA and y_bar.

I now have:
y_bar = y/2

dA = y*dx

yc = (1/2) Integral(y2*dx) / Integral(y*dx)
evaluated from 0 to b

where y = H*sin(pi*x/b)
 
  • #6
33,169
4,853
Yes, that's pretty much it.
 

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