Logarithm Function: Properties and Solutions [Attached Image]

Victim
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Homework Statement

I have attached image of question.[/B]

Homework Equations

all the properties of log
a^(logₘn)=n^(logₘa)[/B]

The Attempt at a Solution

in the attached image
1534508914003-822972847.jpg
[/B]
 

Attachments

  • 1534508914003-822972847.jpg
    1534508914003-822972847.jpg
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##\log _3 \left( a^{\log _3 7} \right)## is of the form ##\log _3 \left( a^y \right)##, Can you simplify this further?
 
George Jones said:
##\log _3 \left( a^{\log _3 7} \right)## is of the form ##\log _3 \left( a^y \right)##, Can you simplify this further?
and then
 
Victim said:
and then
You tell us, George gave you a hint.
 
jedishrfu said:
You tell us, George gave you a hint.
OK by this method I got a=20 b=38 c=√(11)-25
Then they are in power of log₃7,log₇11 and log₁₁25.How to solve these powers
 
Victim said:
OK by this method I got a=20 b=38 c=√(11)-25
Then they are in power of log₃7,log₇11 and log₁₁25.How to solve these powers
The problem states that a, b, and c are positive. The value you give for c, ##\ \sqrt{11\,}-25\,,\ ## is negative.

Moreover, as it turns out, a, b, and c are all irrational. Fortunately, you do not need to solve for any of them to solve this problem.

Here is a hint that's different than the one given by George Jones.
Notice that ##\displaystyle \ X^{Y^ 2}=X^{Y\cdot Y}=\left(X^Y\right)^Y \ ##​
.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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