Loop de loop normal force roller coaster

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Homework Help Overview

The discussion revolves around the forces acting on a roller coaster during a loop-de-loop, specifically focusing on normal force, gravitational force (mg), and centripetal force. Participants are examining the relationships between these forces at different points in the loop, including the bottom, side, and top of the loop.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equations for normal force at various points in the loop and question the role of different forces acting on the roller coaster. They explore the implications of these forces on the motion of the coaster and seek validation for their reasoning.

Discussion Status

Some participants have provided affirmations regarding the correctness of the equations presented, while others have raised questions about the completeness of the force analysis, particularly at the sides of the loop. There is an ongoing exploration of the relationship between centripetal acceleration and linear acceleration, indicating a productive dialogue.

Contextual Notes

Participants are preparing for the MCAT, which may impose specific constraints on the types of questions and conceptual understanding required. There is a focus on validating assumptions and clarifying definitions related to forces in circular motion.

johnj7
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hello, I'm trying to study for the mcat, and I have a conceptual question about normal force, mg, and centripetal force during a loop-de-loop on a roller coaster.

Could you validate these force equations?

1. At the very bottom of the loop:
N - mg = ma = mv^2 / r
N = mg + ma

2. At the side of the loop:
N = ma = mv^2 / r
the normal force is providing all of the centripetal acceleration

3. At the very top of the loop:
N + mg = ma = mv^2 / r
N = ma - mg

Thus the normal force would be the greatest at the bottom of the loop, and least at the top of the loop.

Is all of this correct?

also, for the very top of the loop, since normal force and weight are directed downward, what force prevents the cart from just dropping off the tracts?
in relation to the previous question, what is happening on the side of the loop?

thank you very much !
 
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johnj7 said:
hello, I'm trying to study for the mcat, and I have a conceptual question about normal force, mg, and centripetal force during a loop-de-loop on a roller coaster.

Could you validate these force equations?

1. At the very bottom of the loop:
N - mg = ma = mv^2 / r
N = mg + ma
Good.

2. At the side of the loop:
N = ma = mv^2 / r
the normal force is providing all of the centripetal acceleration
Yes, the normal force provides the centripetal acceleration. But it's not the only force acting on the coaster. So N = ma_c ≠ ma

3. At the very top of the loop:
N + mg = ma = mv^2 / r
N = ma - mg
Good.

Thus the normal force would be the greatest at the bottom of the loop, and least at the top of the loop.
Good.

Is all of this correct?

also, for the very top of the loop, since normal force and weight are directed downward, what force prevents the cart from just dropping off the tracts?
The fact that it's moving is what prevents the cart from falling off, not any upward force. (Just like when you toss a ball in the air. What force makes the ball rise? :wink:)
in relation to the previous question, what is happening on the side of the loop?
Same basic idea, but see my note above regarding #2.
 
Hmm, I don't think its highly important, but when the roller coaster is on the side, and the Normal force is not the only force acting.. what would the force equations look like?

ie:

Fy : N = ma_c
Fx : mg = ma

??

also, are centripetal acceleration and linear acceleration related?

if so, how? what variables would I need?

thank you very much!
 
johnj7 said:
Hmm, I don't think its highly important, but when the roller coaster is on the side, and the Normal force is not the only force acting.. what would the force equations look like?

ie:

Fy : N = ma_c
Fx : mg = ma
Good. (Where x is vertical and y is horizontal.)
also, are centripetal acceleration and linear acceleration related?
Not fundamentally.
 

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