Lorentz and Galilean Tranformations

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Icaro Amorim
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Homework Statement


At what speed v will the Galilean and Lorentz expressions for x differ by 0,10 percent?

Homework Equations


xL= (x'+vt')/√(1-(v/c)²) (Lorentz Transformation)
xG=x'+vt' (Galilean Tranformation)

The Attempt at a Solution


I've tried: xG/xL = √(1-(v/c)²) = 0,1%=0,1/100=10^(-3) => 1-(v/c)² = 10^(-6) => v = [√(1-10^-6)]*c~ 0,999999*c.
Where did I go wrong?

The result is 0,0447c according to the book (Introduction to
 
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xG/xL = √(1-(v/c)²) = 1-0,1%

"will differ by 0,10 percent"

not "will be 0.10 percent"
 
Thanks, maajdl.

Greetings from Brazil.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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