Determining Electric and Magnetic Fields: An Electron's Journey

AI Thread Summary
An electron with a velocity of 1.2 * 10^4 m/s in the positive x direction and an acceleration of 2 * 10^12 m/s^2 in the positive z direction is analyzed within a uniform electric field of 20 N/C. To determine the magnetic field, the force equation F = qE + qv x B is applied, requiring knowledge of the force acting on the electron. Newton's second law, F = ma, is relevant for calculating the force, but the x-component of the magnetic field can be any negative value, leading to confusion. It is clarified that when crossing two parallel directions, such as velocity in the x-direction with a magnetic field also in the x-direction, the result is zero. Thus, the x-component of the magnetic field does not affect the electron's motion in this scenario.
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Homework Statement



An electron has a velocity of 1.2 * 10^4 m/s ( in the positive x direction ), and an acceleration of 2 * 10 ^ 12 m/s^2 ( in the positive z direction ) in a uniform electric and magnetic field. If the electric field has a magnitude of 20 N/C ( in the positive z direction), what can you determind about the magnetic field in the region? what can you not determine?

Homework Equations



F = qE + qv x B

The Attempt at a Solution



I need the force quantity to figure out the problem, but am lost besides this. Can someone offer a little help. Thanks.
 
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You are given the acceleration and the mass of an electron is something you can easily look up.
 
Ok I was thinking I was going to be using Newton's second law, but wan't sure. I have the answers to the problem and for the x- vector it says it can be any negative value, can anyone explain why this is?
 
Well you do need to use Newton's 2nd law since F = ma to use the left hand side of your equation. As far as the x-direction of the magnetic field is concerned, what happens when you cross a velocity, that is in the x-direction, with a field in the x-direction? Matter of fact, what happens when you cross any 2 parallel directions together?
 
It would be zero not any negative value correct?

Thanks for all of the help.
 
Yes, any x-component, negative or positive, crossed into the velocity would give 0 here.
 
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