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Lorentz Transformation Rapidity

  1. Oct 25, 2012 #1
    Concerning Rapidity, if tanh(Fi) = v/c, can it be concluded in general that the relative angle of two frames in combination with Lorentz Transformation is tan(theta) = tanh(Fi) = v/c, where theta is the relative angle?
     
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  3. Oct 25, 2012 #2

    Fredrik

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    What do you mean by the "relative angle"?
     
  4. Oct 25, 2012 #3

    robphy

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    Yes,
    [itex] \theta_{21} = \theta_{20}-\theta_{10} [/itex].
     
  5. Oct 29, 2012 #4
    I meants relative angle of the frames.
     
  6. Oct 29, 2012 #5

    Fredrik

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    That's what you said but what does it mean?
     
  7. Oct 30, 2012 #6
    Simply the math connection between rapidity and the angle of two frames, not sure if this is clear?
     
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