Lower Limit of central pressure in Star

[godzilla5002]

Hello,

I was given a question in school that says use the hydrostatic equilibrium equation and mass conservation equation to come up with a lower limit of the central pressure of a star at it's centre. Here is how I think:

1) Refer to the density in both equations as the same and sub one into the other.
2) After I did I get: dp = -[G*M(r)]/[4*pi*R^4]dm,


Now from here, I want to integrate using dm and M(r),, but M(r) is a equation with respect to r... so I can't right. Is there some insight you can give me to derive a lower limit for the pressure.

 

[motoroller]

Hello,

I was given a question in school that says use the hydrostatic equilibrium equation and mass conservation equation to come up with a lower limit of the central pressure of a star at it's centre. Here is how I think:

1) Refer to the density in both equations as the same and sub one into the other.
2) After I did I get: dp = -[G*M(r)]/[4*pi*R^4]dm,


Now from here, I want to integrate using dm and M(r),, but M(r) is a equation with respect to r... so I can't right. Is there some insight you can give me to derive a lower limit for the pressure.

Assuming M(r) is independent of r seems to give the right answer but I can't figure out why. That's the only way I can see of doing the problem.

 

[paco_uk]

I think the trick is to use the fact that we only want a lower limit so if we replace the function with something we can integrate and is definitely lower we will be rigorously correct.

Starting with:

<br /> <br /> dp = -\frac{G m(r)}{4 \pi r^4} dm,<br /> <br />

Integrate from the centre to the surface (I've multiplied by -1 to get P_C positive as that is what we are interested in. We will assume P_S the surface pressure is 0.

<br /> <br /> P_C - P_S = \int_0^{M} \frac{G m(r)}{4 \pi r^4} dm,<br /> <br />

Now, we replace r⁴ (the variable) with R⁴, the constant radius of the star. Since r⁴ \leq R⁴ over the whole range of integration we can be sure that the answer we get is smaller than the true answer.

<br /> <br /> P_C - P_S &gt; \int_0^{M} \frac{G m(r)}{4 \pi R^4} dm,<br /> <br />

Do the integral and get:

<br /> <br /> P_C&gt; \frac{G M^2}{8 \pi R^4} dm,<br /> <br />

This is a rigorous lower limit for the central pressure of the star.