Calculating Maximum Resistance & Inductance for Theater Light Dimmer

AI Thread Summary
The discussion focuses on calculating the maximum inductance (Lmax) and resistance (Rmax) for a theater light dimmer circuit. The user is tasked with determining Lmax required to vary the energy dissipation in a lightbulb rated at 1300 W by a factor of 4, using the relationship between power, voltage, and resistance. They derive a formula for Lmax based on the power ratio and ultimately calculate Lmax as 0.059. The user expresses uncertainty regarding the maximum resistance that can replace the inductor, indicating a need for further clarification on that part of the problem. The conversation highlights the complexities of RLC circuit calculations in practical applications.
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Homework Statement



A typical "light dimmer" used to dim the stage lights in a theater consists of a variable inductor L (whose inductance is adjustable between zero and Lmax) connected in series with a lightbulb. The electrical supply is 120 V (rms) at 60.0 Hz; the lightbulb is rated as 120 V, 1300 W. (a) What Lmax is required if the rate of energy dissipation in the lightbulb is to be varied by a factor of 4 from its upper limit of 1300 W? Assume that the resistance of the lightbulb is independent of its temperature. (b) What would be the maximum resistance of a variable resistor (adjustable between zero and Rmax) which can be used in place of an inductor?

Homework Equations



I know the equations for RLC circuits, and I know P = (i^2)(R)

The Attempt at a Solution



I'm really just stuck. I don't really understand the question. Are we increasing it by a factor of 4 or decreasing it? Can someone get me started on the right track?
 
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I also know that P = V^2 / R

Taking the ratio of Pmax to Pmin we get

Pmax/Pmin = (Imax / Imin)^2 = ( (E/Zmax) / (E/Zmin) )^2 = 4

So

(sqrt( (R^2) + ((w*Lmax)^2) ) / R)^2 = 4

which implies that

Lmax = R / w (when we solve for Lmax in the above equation)

Thus, pluggin in for P = V^2 / R

we get ( (2V^2 / P) / w) = Lmax

Solving, I get Lmax = .059. Does this seem correct?

Now what about part b. Not sure about that one.
 
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