Mag force between two wires with opposite charges

AI Thread Summary
The discussion focuses on calculating the magnetic field generated by two parallel wires carrying currents of 5.00A in opposite directions, separated by 10cm. The magnetic field at a point midway between the wires is found to be zero due to the cancellation of the fields, while at points P1 and P2, the fields subtract due to their opposite directions. The right-hand rule (RHR) is emphasized for determining the direction of the magnetic fields produced by each wire. The conversation also touches on practical applications, such as the twisting of power supply wires to minimize magnetic interference. Overall, the correct approach involves using the vector sum of the individual magnetic fields, taking into account their directions based on current flow.
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Homework Statement


Two wires shown in figure p19.48 carry currents of 5.00A in opposite directions and are separated by 10cm. Find direction and magnitude of the net mag field.

(a) at a point midway between the wires. (b) at point P1 (c) at point P2

Homework Equations


B=B1+B2??
B= u0I / 2pir


The Attempt at a Solution


How would i approach a question like this? How does opposite charges affect the sign in the equation B1+B2?

Thanks!
 

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The equation you cite is for the magnetic field due to a long straight wire

\vec{B} = \frac{\mu I}{2 \pi R}

and as you state, the total magnetic field is the vector sum of the two individual fields.

The fact that the currents move in opposite directions will change the direction of the magnetic field lines for one wire vs. the other. You can use the right hand rule for wires to figure these directions out. For example, if you were looking directly down the length of a wire that was carrying current towards you, the magnetic field lines would be counterclockwise circles (point your thumb at your face and your fingers curl in the cc direction). If the wire carried current away from you, the field would be clockwise.
 
so for the first part (a):

B=B1-B2

B1= u5A / 2pi(.05)
B2= (u5A / 2pi(.05)

B= (u5A / 2pi(.05)) - (u5A / 2pi(.05))
the magnitude of the field in part a would be zero??
 
No, using the RHR you should find that between the wires the fields actually add together and their direction points into the page. At points P1 and P2 the fields are in opposite directions and therefore subtract.

This is why the power supply wires inside a computer are twisted together. Since the power and return wires carry current in opposite directions, twisting them together makes the magnetic fields almost completely cancel out.
 
maybe i need practice with the right hand rule lol

when i apply the rhr for the first wire, my thumb points north and fingers clockwise

when i apply the rhr for the second wire, my thumbs point south and the fingers counter clockwise.

how exactly is direction changing with distance? this is frustrating haha
 
You did the RHR correctly, but in between the wires the clockwise direction from the first wire gives you a field that points into the page on the right side of it (i.e. in between the wires) and the same is true for the second wire.
 
ok so let me understand,

for (a)

B=-B1-B2

for (b)

B=-B1+B2

for (c)

B=B1-B2

is this how it would be?
 
yes, that should give you the correct magnitudes.
 
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