Magnetic field for a single-layer solenoid

asdf1
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does anybody know why the magnetic field for a single-layer solenoid of a point in the middle of the solenoid axial field is
H=[(4pini)/(10L)]*{[L+2x/[2(D^2+(L+2x)^2]^(0.5) +
[L-2x/[2(D^2+(L-2x)^2]^(0.5)}
where L is the length of a finite solenoid, D is the diameter
 
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You can calculate the on axis magnetic field of a current loop. To obtain the on axis field of a finite solenoid, just integrate.
 
i did... I'm stuck on where does[(4pini)/(10L)] come from?
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.
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