What Is the Range of Magnetic Field Values Inside a Toroid?

AI Thread Summary
The discussion focuses on calculating the magnetic field values inside a toroid with specified inner and outer diameters and a current. The correct approach involves using the formula B = μ0/2π * NI/r, where the inner radius gives the maximum magnetic field and the outer radius gives the minimum. Participants clarify that the magnetic field strength decreases as the radius increases, leading to confusion about which radius to use for calculations. The final equations for B maximum and B minimum are confirmed as B maximum = μ0 * 500 * 23 / 2π * (0.494/2) and B minimum = μ0 * 500 * 23 / 2π * (0.572/2). Understanding the relationship between radius and magnetic field strength is crucial for accurate calculations.
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Homework Statement



A toroid has a 49.4-cm inner diameter and a 57.4-cm outer diameter. It carries a 23 A current in its 500 coils. Determine the range of values for B inside the toroid.

A) Bmaximum = ?
B) Bminimum = ?

Homework Equations



B = mu0/2pi * NI/r[/B]

The Attempt at a Solution


I tried plugging in the values from the problem but I am not sure where I am going wrong.

B minimum = Mu0 * 500 * 23 / 2 pi * (.494/2)

B maximum = Mu0 * 500 * 23 / 2 pi * (.572/2)

Am I doing something wrong with the radius? Is the B minimum not thre inner r and the maximum the outer r?
 
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Is the B minimum not the inner r and the maximum the outer r?

No it's the other way around.

http://physics.aalto.fi/pub/kurssit/Tfy-3.15xx/Tp_ohjeet/33en.pdf

..the magnetic field strength decreases inversely proportional to the distance from the torus center

If you divide by a smaller number (eg inner radius) you get a larger result (eg maximum B).
 
CWatters said:
No it's the other way around.

http://physics.aalto.fi/pub/kurssit/Tfy-3.15xx/Tp_ohjeet/33en.pdf
If you divide by a smaller number (eg inner radius) you get a larger result (eg maximum B).

So the equation becomes

B maximum = Mu0 * 500 * 23 / 2 pi * (.494/2)

B minimum = Mu0 * 500 * 23 / 2 pi * (.572/2)

?
 
Yes.
 
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