A small loop of area A is placed inside a long solenoid that has n turns per meter and carries a sinusoidally varying current of amplitude i. The central axes of the loop and solenoid coincide. If i = i0sin ωt, find the emf in the loop.
EMFinduced = - d([tex]\phi[/tex]B)/ dt
The product of B and A = A[tex]\mu[/tex]0ni0sin (ωt)
So the derivative of [tex]\phi[/tex]B with respect to time:
=A[tex]\mu[/tex]0ni0cos (ωt) ω
EMFinduced = - A[tex]\mu[/tex]0ni0cos (ωt) ω
Apparently this is incorrect. I'm sorry about the sloppy formatting, could someone help me out with this?