A small loop of area A is placed inside a long solenoid that has n turns per meter and carries a sinusoidally varying current of amplitude i. The central axes of the loop and solenoid coincide. If i = i0sin ωt, find the emf in the loop. EMFinduced = - d([tex]\phi[/tex]B)/ dt [tex]\phi[/tex]B=BA Bsolenoid= [tex]\mu[/tex]0ni The product of B and A = A[tex]\mu[/tex]0ni0sin (ωt) So the derivative of [tex]\phi[/tex]B with respect to time: =A[tex]\mu[/tex]0ni0cos (ωt) ω so; EMFinduced = - A[tex]\mu[/tex]0ni0cos (ωt) ω Apparently this is incorrect. I'm sorry about the sloppy formatting, could someone help me out with this?