Magnetic Field Problem - Tricky Wording.

AI Thread Summary
The problem involves an electron moving in a helical path within a uniform magnetic field of 0.300 T, with a pitch of 6.00 μm and a magnetic force of 2.00 x 10^-15 N acting on it. The term "pitch of the path" refers to the distance along the axis for one complete turn of the helix, indicating the spiral nature of the motion. Although the helical path has curvature, centripetal force does apply due to the acceleration perpendicular to the helix axis. However, the details of centripetal force are not necessary to solve the problem since the force and magnetic field strength are provided. Understanding these concepts is crucial for accurately interpreting the problem's wording and solving for the electron's speed.
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Homework Statement



21. An electron follows a helical path in a uniform magnetic field of magnitude 0.300{\textcolor[rgb]{1.00,1.00,1.00}{.}}T. The pitch of the path is 6.00{\textcolor[rgb]{1.00,1.00,1.00}{.}}{\mu}m, and the magnitude of the magnetic force on the electron is {2.00{\times}{{10}^{-15}}}{\textcolor[rgb]{1.00,1.00,1.00}{.}}N. What is the electron's speed?

Homework Equations



<br /> {\vec{F}_{E}} = {q{\vec{E}}}<br />

<br /> {\Delta{V}_{p}} = {{-}{\int_{r_{0}}^{r_{1}}}{\vec{E}_{p1}(r)}{\cdot}{d{\vec{r}}}}<br />

<br /> {\vec{E}} = {{-}{\nabla}{V(r)}}<br />

<br /> {\vec{E}} = {{-}{\frac{\partial}{\partial{r}}}{\left[{V(r)}\right]}{\hat{r}}}<br />

<br /> {\vec{F}_{B}} = {q{\vec{v}}{\times}{\vec{B}}}<br />

The Attempt at a Solution



This problem isn't so hard to solve, as intrepreting the information the problem is giving.

Like, when the problem says,

PFStudent said:
The pitch of the path is 6.00{\textcolor[rgb]{1.00,1.00,1.00}{.}}{\mu}m,

What exactly do they mean by "pitch of the path," and why are they giving it as a measure of distance (ie. {m})?

In addition, they mention that the electron, "follows a helical path," by helical path--they're basically saying an upward spiral path, is that correct?

Also, since a helical path has some curvature to it, does the centripetal force apply to this problem? (even though a helical path is not the same as going around in a cricle)

And if the centripetal force does apply, why?

Any help is appreciated.

Thanks,

-PFStudent
 
Last edited:
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Hey,

Yea..., so does anyone have any ideas on this?

Thanks,

-PFStudent
 
Last edited:
Hey,

Yea, still a little stuck on this,..does anyone know how the wording in this problem is supposed to be interpreted?

Thanks,

-PFStudent
 
PFStudent said:
What exactly do they mean by "pitch of the path," and why are they giving it as a measure of distance (ie. {m})?
The pitch of a helix is the distance along the axis for one complete turn. If it had a pitch of zero, it would just be a circle.

In addition, they mention that the electron, "follows a helical path," by helical path--they're basically saying an upward spiral path, is that correct?
It's a spiral.

Also, since a helical path has some curvature to it, does the centripetal force apply to this problem? (even though a helical path is not the same as going around in a cricle)

And if the centripetal force does apply, why?
Sure it will have a centripetal force, since it will have an acceleration perpendicular to the helix axis. But you don't need to worry about the details to solve this problem, since you're given the force and the magnetic field strength.
 
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