PFStudent
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Homework Statement
21. An electron follows a helical path in a uniform magnetic field of magnitude 0.300{\textcolor[rgb]{1.00,1.00,1.00}{.}}T. The pitch of the path is 6.00{\textcolor[rgb]{1.00,1.00,1.00}{.}}{\mu}m, and the magnitude of the magnetic force on the electron is {2.00{\times}{{10}^{-15}}}{\textcolor[rgb]{1.00,1.00,1.00}{.}}N. What is the electron's speed?
Homework Equations
<br /> {\vec{F}_{E}} = {q{\vec{E}}}<br />
<br /> {\Delta{V}_{p}} = {{-}{\int_{r_{0}}^{r_{1}}}{\vec{E}_{p1}(r)}{\cdot}{d{\vec{r}}}}<br />
<br /> {\vec{E}} = {{-}{\nabla}{V(r)}}<br />
<br /> {\vec{E}} = {{-}{\frac{\partial}{\partial{r}}}{\left[{V(r)}\right]}{\hat{r}}}<br />
<br /> {\vec{F}_{B}} = {q{\vec{v}}{\times}{\vec{B}}}<br />
The Attempt at a Solution
This problem isn't so hard to solve, as intrepreting the information the problem is giving.
Like, when the problem says,
PFStudent said:The pitch of the path is 6.00{\textcolor[rgb]{1.00,1.00,1.00}{.}}{\mu}m,
What exactly do they mean by "pitch of the path," and why are they giving it as a measure of distance (ie. {m})?
In addition, they mention that the electron, "follows a helical path," by helical path--they're basically saying an upward spiral path, is that correct?
Also, since a helical path has some curvature to it, does the centripetal force apply to this problem? (even though a helical path is not the same as going around in a cricle)
And if the centripetal force does apply, why?
Any help is appreciated.
Thanks,
-PFStudent
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