smellsey
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Homework Statement
You have 10 m of 0.55 mm diameter copper wire and a battery capable of passing 13 A through the wire. What magnetic field strength could you obtain inside a 2.8 cm diameter solenoid wound with the wire as closely spaced as possible?
Homework Equations
Turns of a solenoid = length of wire/ (2\pi * radius of solenoid)
B = ( \mu*turns of a solenoid * Current)/(\sqrt{}(4(radius of solenoid)^2+(radius of copper wire)^2 where \mu = 4\pi *10^-7
I believe that's right once you do the integration
The Attempt at a Solution
I tried to solve this and I got B = 0.27 T but it isn't right! I've tried over and over again, but I can't see to get the right answer.
Thanks!