Magnetic field strength quick question

AI Thread Summary
The discussion revolves around calculating the magnetic field strength between two parallel wires carrying currents in opposite directions. For the midpoint between the wires, the magnetic fields add up, resulting in a strength of 5.6 A m^-1. In the second part, the user is confused about whether to add or subtract the magnetic field strengths at a specific point, as the fields generated by the wires have opposite directions. Clarification is provided using the right-hand rule to determine the direction of the magnetic fields, emphasizing that at the specified point, the fields should be subtracted. The user expresses gratitude for the clear explanation, highlighting the effectiveness of the guidance received.
debwaldy
Messages
34
Reaction score
0

Homework Statement


Two very long parallel wires which are 20cm apart ,carry currents of 1.5A and 2.0A respectively, flowing in opposite directions. Calculate the magnetic field strength at following points in plane of two wires
(i) midway between wires
(ii)at a point 10cm from the wire carrying the larger current and 30 cm from the other wire


Homework Equations


I have been using the formula H = I/2*pi*R

The Attempt at a Solution


I think i could do part (i) as I knew that the magnetic field strengths add in the middle so i just plugged into the formula using R=0.1 and got an answer of
5.6 A m^-1

However in part (ii) I am slightly confused.
I have said the following:
H = 1.5/2*pi*.3 + 2.0/2*pi*0.1
Is this equation correct or should i be subtracting one magnetic field strength
from the other.andif so which one?i don't really understand
any help or tips would be v much appreciated thanks:biggrin:
 
Physics news on Phys.org
The fields aren't going in the same direction. Do you know how to find the direction of the field generated by a wire (the "thumb rule") ? You put your thumb of your right hand in the direction of the wire and the direction that your fingers are curling is the direction of the field. In the middle of the wire the fields go in the same direction even though the currents are in opposite directions because the middle of the wire is to the right of one and to the left of the other one. But in (ii) the point is on the same side as both of the wires so since the fingers curl in opposite directions, the fields will have opposite directions.
 
oh i think i understand now thanks a million,looked in loads of books but none explained it in the simple straightforward manner that you did
cheers debs:-p
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top