Calculating Electron Speed in a Magnetic Field

[Andreii]

Hi everyone

I would like to ask, how can i resolve this task:

electron is moving inside the magnetic field with density 0.002 T on the shape of screw with radious 2 cm (centimeters) and height of screw 5 cm. What is electron's speed? The result is 7.6 Mm/s but I am trying to see how do i get this result?

Thank you for formulas and tips.

 

[Astronuc]

http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/maspec.html#c2

The force induced by the magetic field on the charged particle must equal the centripetal force of the particle.

See also - http://hyperphysics.phy-astr.gsu.edu/hbase/magnetic/magfor.html

Look at Lorentz force law.

 

[quicknote]

Hello there,

To calculate the speed of an electron moving in a magnetic field, we can use the formula v = B*q/m, where v is the speed, B is the magnetic field density, q is the charge of the electron, and m is the mass of the electron.

In this case, we know that B = 0.002 T and the dimensions of the screw, but we still need to determine the values of q and m. The charge of an electron is a fundamental constant and is equal to -1.602 x 10^-19 Coulombs. The mass of an electron is 9.109 x 10^-31 kilograms.

Using these values and plugging them into the formula, we can calculate the speed of the electron to be approximately 7.6 Mm/s. It is important to note that this is an approximation, as there may be other factors at play that could affect the speed of the electron.

I hope this helps! Remember to always double check your units and use the correct values for the constants. If you have any further questions, please don't hesitate to ask. Happy calculating!