Magnetic Fields and insulated wires

AI Thread Summary
The discussion revolves around calculating the magnetic fields at two points near two insulated wires carrying a 5.0 A current each. The magnetic field at point 1, located between the wires, is calculated to be 5.2 x 10^-5 T directed out of the page, while at point 2, the fields cancel each other, resulting in a net magnetic field of 0. Some participants express confusion about the calculations and the positioning of the points, requesting clarification and visual aids. The calculations utilize the formula B = [(mu)I]/2(pi)r, with specific distances derived from the geometry of the wire arrangement. Overall, the thread highlights the importance of clear diagrams and accurate calculations in understanding magnetic field interactions.
Mitchtwitchita
Messages
187
Reaction score
0

Homework Statement



Two insulated wires cross at a 30 degree angle but do not make electrical contact. Each wire carries a 5.0 A current to the left through their respective wires. There are two points. One point lies between the bottom 150 degree angle, and the other lies between the right 30 degree angle. Each point is 4.0 cm from the intersection and equally distant from both wires. What are the magnitude and direction of the magnetic fields at points 1 and 2?

Homework Equations



B = [(mu)I]/2(pi)r

The Attempt at a Solution



I1 = I2 = 5.0 A
r1 = r2 = 0.040msin75degrees = 0.039m
r3 = r4 = 0.040msin15degrees = 0.010m

Bwire1onp1 = Bwire2onp1 = [(Mu)I]/[2(pi)r]
=[(1.257 x 10^-6 T*m/A)(5.0 A)]/[2(pi)(0.039 m)]
=2.6 x 10^-5 T

Bwire1onp2 = Bwire2onp2 = [(1.257 x 10^-6 T*m/A)(5.0 A)]/[2(pi)(0.010 m)]
=1.0 x 10^-4 T

Since Bw1onp1 and Bw2onp1 are both out of the page, then they add to give 5.2 x 10^-5 T out of the page

Since Bw1onp2 comes out of the page, and Bw2onp2 goes into the page, then they cancel to give 0

This doesn't seem right to me, can anybody tell me if I'm doing something wrong please?
 
Physics news on Phys.org
Could you please show a picture? It is not clear where those points are.

ehild
 
IMG_0002.jpg
 
You are right.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top