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Magnetism - Current in a Wire

  1. Sep 19, 2012 #1
    1. The problem statement, all variables and given/known data

    A long horizontal wire carries a current of 48 A. A second wire, made of 3.0 mm diameter copper wire and parallel to the first, is kept in suspension magnetically 15 cm below. Determine the magnitude of the current in the lower wire.

    2. Relevant equations

    μI / 2∏r

    3. The attempt at a solution

    B = (1.256*10^-6)(48 A) / (2∏)(.15 m)^2
    B = 4.2639 * 10 ^-4 T

    B(2∏r) / μ = I

    (4.2639 * 10^-4 T)(2∏)(1.5*10^-3 m)/(1.256 * 10^-6)

    I = 3.19 A
     

    Attached Files:

  2. jcsd
  3. Sep 20, 2012 #2

    You made an arithmetic mistake .:wink:

    B= [4∏*10^-7]*[48]/(2∏*0.15) = 6.4*10^-5 T
     
  4. Sep 20, 2012 #3
    Oops! Thank you for that.
     
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