Magnetism Question Can't figure it out

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The problem involves calculating the electric charge of a bullet fired in a magnetic field. The Earth's magnetic field is given as 5.5 x 10^-5 T, directed north at a 40° angle below the horizontal. The bullet moves north at 700 m/s and at an angle of 19° above the horizontal, experiencing a magnetic force of 3.9 x 10^-10 N directed east. The equation used is F = qvBsin(theta), where the angle between the velocity and magnetic field is adjusted to 59°. The solution aims to determine the bullet's charge and its algebraic sign.
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Homework Statement



In a certain region, the Earth's magnetic field has a magnitude of 5.5 x 10-5 T and is directed north at an angle of 40° below the horizontal. An electrically charged bullet is fired north and 19° above the horizontal, with a speed of 700 m/s. The magnetic force on the bullet is 3.9 x 10-10 N, directed due east. Determine the bullet's electric charge, including its algebraic sign (+ or -).

Homework Equations



F=qvBsintheta

The Attempt at a Solution



3.9E-10N= q* 700m/s(V)*5.5E-5T (B)*sin19
=3.1E-8N
 
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Angle between v and B is ...?
 
59degrees?
 
Substitute this value in the problem instead of 19 degrees.
 
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