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## Homework Statement

A baar magnet inserted into a coil of 500 turns induces a potential difference of

**1.5 V**across the coil. Determine the induced potential difference when;

**a> 250 turn coilis used.**

b> the bar magnet is moved twice as fast through the coil.

c> three identical magnets are inserted at once, side by side

d> all three of the above charges occur simultaneously.

b> the bar magnet is moved twice as fast through the coil.

c> three identical magnets are inserted at once, side by side

d> all three of the above charges occur simultaneously.

## The Attempt at a Solution

**a>**1.5V/ 500 = V/ 250

solve for V, V=

**0.75 V**

**b>**im not quite sure, Im guessing there will be no difference in the voltage?

**c>**(0.75V)(3) =

**2.25V**

**d>**do I just add the voltages from a, b, and c?

I would greatly appreciate it if anyone could confirm the answers I got or let me know if Im on the right track with b and d?

Thankyou in advance!