A baar magnet inserted into a coil of 500 turns induces a potential difference of 1.5 V across the coil. Determine the induced potential difference when;
a> 250 turn coilis used.
b> the bar magnet is moved twice as fast through the coil.
c> three identical magnets are inserted at once, side by side
d> all three of the above charges occur simultaneously.
The Attempt at a Solution
a> 1.5V/ 500 = V/ 250
solve for V, V= 0.75 V
b> im not quite sure, Im guessing there will be no difference in the voltage?
c> (0.75V)(3) = 2.25V
d> do I just add the voltages from a, b, and c?
I would greatly appreciate it if anyone could confirm the answers I got or let me know if Im on the right track with b and d?
Thankyou in advance!