Magnitude of Acceleration on Merry-Go-Round

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The discussion focuses on calculating the magnitude of acceleration for a child on a merry-go-round. The child, weighing 30 kg, experiences centripetal acceleration as the merry-go-round accelerates to a speed of 1.7 rotations per second. The correct angular velocity is calculated as 10.68 rad/s, and angular acceleration is determined to be 0.427 rad/s². A key error noted is the confusion between diameter and radius, emphasizing the need to use the radius for accurate calculations. The final acceleration calculation should reflect this correction to yield the correct result.
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Homework Statement


At a playground you let your kid sister (30 kg) kneel on the surface (near the edge) of a 2.1 meter diameter merry-go-round. You push the merry-go-round so that it constantly accelerates from rest to a final speed of 1.7 rotations per second at the end of a 25 second interval. (please complete all questions using radians)
After it comes up to speed, you stop pushing and the merry-go-round continues to run at a constant rate of 1.7 rotations per second. What is the magnitude of your sister's acceleration, if any?

Homework Equations


V is the tangental velocity in m/s
r is radius of circle in meters
ω is angular velocity in radians/sec
a is in m/s²
[/B]
1.7 rotations per second x 2π rad/rev = 10.68 rad/s
ang. acc. = Δω/Δt = 10.68/25 = 0.427 rad/s²
134 rad x 1 rev/2πrad = 21.25 rev

The Attempt at a Solution


I got the first part of the question right, but I have no idea what I am doing wrong for the last part shown above. This is what I did:

a = rω² = (2.1)(10.68)² = 240 m/s²
[/B]
 
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Diameter =/= radius!
 
in the first place, 2.1 meters is the diameter, and you have to use the radius. In the second place, as far as I can see there is only one question.
 
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