Magnitude of Forces exerted by charges.

AI Thread Summary
The discussion focuses on calculating the forces exerted by two charges, q1 and q2, using Coulomb's law. The calculated force on q1 is 23.973 N, which raises questions about its magnitude. Participants clarify that while the forces on both charges should have the same magnitude, their directions differ based on the nature of the charges. The importance of correctly converting microcoulombs to coulombs is emphasized, as errors in this conversion can lead to incorrect calculations. Ultimately, the discussion concludes that the signs of the charges do not affect the magnitude of the forces, which are always expressed as positive values.
genu
Messages
22
Reaction score
0

Homework Statement


A charge q1 = 4.0 μC is at the origin and a charge q2 = 6.0 μC is on the x-axis at x = 3.0 m.

Find the magnitude of the force exerted on q1. Give your answer in N rounded to 3 decimal places.

Find the magnitude of the force exerted on q2. Give your answer in N rounded to 3 decimal places

Homework Equations



F=(k(q1*q2))/r^2

The Attempt at a Solution


I converted μC to C
and I got 23.973N for the first part. (isn't this too much force for a charge?)
The second part, shouldn't the force be the same?
 
Physics news on Phys.org
Please show more of your work. What exactly are the numbers you put in the equation?

Yes, in the second part the force should be the same. Can you explain why?
 
q1 = 4.0 μC = 4.0 * 10^-9 C
q2 = 6.0 μC = 6.0 * 10^-9 C

here is what I did
F = (8.99 * 10^9 * 4.0 * 10^-9 C * 6.0 * 10^-9 C)/3.0^2 = 23.973N

Now that I think about it, the difference between the 2 questions should be the direction of the force, but the same magnitude.
 
Redo your calculation for two reasons

1. 1.0 μC = 1.0 * 10-6 C
2. Just by looking at the powers of 10 and your answer, it is clear that you forgot to multiply by the second 10-9.
 
oh...I see, thank for pointing that out.

As far as the signs go, do the answers have different signs?

Although, they don't specify as to whether the charges are positive or negative.
 
Signs don't matter here. You are asked to find magnitudes and these are always positive.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
I was thinking using 2 purple mattress samples, and taping them together, I do want other ideas though, the main guidelines are; Must have a volume LESS than 1600 cubic centimeters, and CAN'T exceed 25 cm in ANY direction. Must be LESS than 1 kg. NO parachutes. NO glue or Tape can touch the egg. MUST be able to take egg out in less than 1 minute. Grade A large eggs will be used.
Back
Top