Magnitude of the Electric Force on q

AI Thread Summary
To find the magnitude of the electric force on charge q, use Coulomb’s Law, F = kq1q2/r^2. With given values a = 3.0 mm, b = 4.0 mm, Q1 = -60 nC, Q2 = 80 nC, and q = 30 nC, the calculated force is F = 1.0 N. The discussion emphasizes the need to calculate the forces between Q1 and q, and Q2 and q, noting that both forces act in the same direction and should be added. The beginner expresses difficulty in understanding net force calculations but is encouraged to focus on the relevant forces acting on q. Mastering these calculations is essential for grasping electric force concepts.
wkn0524
Messages
3
Reaction score
0
1. If a = 3.0 mm, b = 4.0 mm, Q1 = -60 nC, Q2 = 80 nC, and q = 30 nC in the Figure Q1,
what is the magnitude of the electric force on q?

2. F = kq1q2/r^2 Coulomb’s Law
3. Answer is F=1.0N

I'm a beginner in electrical study, i stuck on the net force.

My steps are:
F1=kQ1Q2/a^2 , F2= kQ2q/r^2

 

Attachments

  • Untitledasd.png
    Untitledasd.png
    5 KB · Views: 1,024
Physics news on Phys.org
F1 is the force between Q1 and Q2, this is not relevant here. Can you calculate the force between Q1 and q? Did you calculate F2? As both forces on q point in the same direction, just add them.
 
mfb said:
F1 is the force between Q1 and Q2, this is not relevant here. Can you calculate the force between Q1 and q? Did you calculate F2? As both forces on q point in the same direction, just add them.

Sure, I'm trying out more than 1 hour. Trying again.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top