Making the sum of 2 resistors independent of 1 of them

AI Thread Summary
In a series circuit with two resistors, the total current is dependent on both resistances, and simply increasing one resistor's value does not make the current independent of the other. A proposed solution involves using a double-potentiometer to adjust one resistance inversely to the other, maintaining constant total resistance. However, the consensus is that making one resistor infinitely large is the only way to achieve independence from that resistor's value. The discussion highlights the limitations of calculators versus analog measurements in discerning minute differences in current. Ultimately, the conclusion emphasizes that the current will always be influenced by both resistors unless one approaches infinity.
brainbaby
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I am really not sure about this ...
I may be generalizing it ...but anyway...

suppose we have two resistors in series...connected by ofcourse a voltage source...and a certain amount of total current is flowing through the whole circuit..

now if we want to make the total current totally independent of the value of one resistance then do we have to make the value of other resistor very high...?

independent here means...no matter what is the value of that resistance.. it does not effect the total current
 
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brainbaby said:
I am really not sure about this ...
I may be generalizing it ...but anyway...

suppose we have two resistors in series...connected by ofcourse a voltage source...and a certain amount of total current is flowing through the whole circuit..

now if we want to make the total current totally independent of the value of one resistance then do we have to make the value of other resistor very high...?

independent here means...no matter what is the value of that resistance.. it does not effect the total current
The current is entirely dependent on the sum of the two resistors so the only way to to what you are asking (assuming I understand what you are asking, which I'm not sure about since what you are asking really doesn't make sense) is to devise a double-potentiometer with a single control mechanism so that as one of the two resistances goes up, the other goes down by an equal amount so as to keep the total resistance the same.
 
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Compare the current through a 1-Mega-Ohm resitor with the current drawn by a series combination of 1 Megohm and 1 Milliohm.
 
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LvW said:
Compare the current through a 1-Mega-Ohm resitor with the current drawn by a series combination of 1 Megohm and 1 Milliohm.
with 1megaohm individual resistor ...current is 2*10^-5A...whereas with series combination it is 1.999999998*10^-5A...

but what is the conclusion in reference to the problem...?
 
brainbaby said:
with 1megaohm individual resistor ...current is 2*10^-5A...whereas with series combination it is 1.999999998*10^-5A...

but what is the conclusion in reference to the problem...?
I believe I see what he is getting at, but I think my response more directly addresses your question.
 
phinds said:
I believe I see what he is getting at, but I think my response more directly addresses your question.
can you please conclude...the problem...i am really stuck...
 
brainbaby said:
can you please conclude...the problem...i am really stuck...
I think I answered it completely already. Did you not understand my first post?
 
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phinds said:
I think I answered it completely already. Did you not understand my first post?
but in your first post current still seem to be dependent on both resistances...i am asking thst would it be possible to make current independent to anyone resistance just by increasing the other resistance to a higher value...
 
brainbaby said:
but in your first post current still seem to be dependent on both resistances...i am asking thst would it be possible to make current independent to anyone resistance just by increasing the other resistance to a higher value...
And my solution shows clearly that the answer to that question is a resounding NO. You really need to study what I said.
 
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phinds said:
And my solution shows clearly that the answer to that question is a resounding NO. You really need to study what I said.
OK...then what logic LvW is talking about
 
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brainbaby said:
OK...then what logic LvW is talking about
He is attempting, I believe, somewhat indirectly, go get you to arrive at the same conclusion I presented you with.
 
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  • #12
Yes, it is easy. Just make one of the resistors infinite.

We are doomed.
 
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  • #13
brainbaby said:
with 1megaohm individual resistor ...current is 2*10^-5A...whereas with series combination it is 1.999999998*10^-5A...

but what is the conclusion in reference to the problem...?

That's the trouble with calculators versus slide rules.

Mother Nature is analog.

If you can discern the difference between those two currents with any real measuring device ,,,,

So -
As an engineer , to how many significant digits do you wish to push the question ?
As a mathematician, how would you describe the behavior of the limit as one of the individual resistors approaches infinity ?
 
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