Mass Defect: Pb-210 Nuclear Binding Energy

AI Thread Summary
The discussion focuses on calculating the mass defect and binding energy for lead-210 (Pb-210). The initial calculation for the mass defect was incorrect due to the omission of the mass of electrons. After correcting for the electron mass, the mass defect was recalculated to be 1.72 atomic mass units (u). The binding energy and binding energy per nucleon were also to be determined but were not explicitly calculated in the provided content. Accurate calculations require careful consideration of all components, including electrons, for precise results.
MrDMD83
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Homework Statement



For lead N=210 Z=82 Pb (atomic mass = 209.984163 u) obtain each of the following:
(a) The mass defect in atomic mass units
u
(b) the binding energy (in MeV)
MeV
(c) the binding energy per nucleon (in MeV)
MeV


Homework Equations





The Attempt at a Solution



a) 82 x 1.6726e-27 kg + 128 x 1.6749e-27 kg= 3.515e-25 kg

3.515e-25kg x 1u/1.6605e-27= 211.708

211.708-209.984163= 1.72u but it says my answer is wrong.
 
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Nevermind. I forgot to initially subtract the mass of the 82 electrons from the mass of entire atom.
 

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