Mass of Particle in 0.200T Magnetic Field

AI Thread Summary
To find the mass of a particle moving in a 0.200 T magnetic field with a kinetic energy of 3.2 x 10^-19 J, the equations for kinetic energy and circular motion are used. The relationship mv = qBr is established, where q is the charge and r is the radius of the path. By substituting the known values, mv is calculated as 3.2 x 10^-21 kg·m/s. To separate mass and velocity, the kinetic energy equation is rewritten as ke = ½(mv)v, allowing for the calculation of velocity. This approach ultimately leads to the determination of the particle's mass.
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Homework Statement


what is the mass of a particle which travels in a circular path with a kinetic energy of 3.2 x 10 ^-19 J moving perpendicular to a 0.200t magnetic field if it has a charge of 1.6 x10 ^-19 C and the path radius is 10 cm

Homework Equations


ke= 1/2 mv^2

mv^2/r = qvB

r = mv^2/qvB = mv/qB

mv = qBr

The Attempt at a Solution

mv =qbr
mv = 1.6 x10 ^-19 C x 0.200 T x 0.1 M
mv = 3.2x 10 ^-21

i can't figure out how to separate the mass and velocity using ke=1/2mv^2
any help is much appreciated
 
Last edited:
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Write ke=1/2mv^2 as ke = ½(mv)v and replace the mv with value you found. Since you know the value of ke, you can then easily find v.
 

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