Mass of air leaving a room with temp raised.

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To determine the mass of air leaving a room when the temperature increases from 17.2°C to 25°C, the ideal gas law is applied. The calculations involve the initial and final states of the air, using the molar mass of 36.3 g/mol and maintaining a pressure of 43.6 kPa. The formula derived indicates that the mass difference can be calculated based on the change in temperature and the volume of the room. The approach seems correct, focusing on the relationship between pressure, volume, and temperature. Accurate calculations will yield the mass of air that exits the room in kilograms.
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A room of volume 68 m^3 contains air having an average molar mass of 36.3 g/mol. If the temperature of the room is raised from 17.2C to 25C, what mass of air will leave the room? Assume that the air pressure in the room is maintained at 43.6 kPa. Answer in units of kg.
Been messing around with the following to get it into the right form, am I on the right track?

P_0V = n_1RT = \frac{m_1}{M}RT_1

P_0V = n_2RT_2 = \frac{m_2}{M}RT_2

m_1-m_2 = \frac{P_0VM}{R} \times (\frac{1}{T_1}-\frac{1}{T_2})
 
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Yo, that looks good to me.
 

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