Mass-to-Charge Ratio of an Ion in Mass Spectrometer

AI Thread Summary
The discussion focuses on calculating the mass-to-charge ratio (m/q) of an ion in a mass spectrometer using given electric and magnetic fields. The participant initially calculated the velocity (v) as 51851 m/s but later recognized that this value was inaccurate due to the precision of the input numbers. The correct approach emphasizes that the exercise specifically requests m/q rather than m. The calculations ultimately yield a mass-to-charge ratio that closely aligns with that of a known particle, suggesting a validation of the method used. The conversation highlights the importance of precision and clarity in solving physics problems.
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Homework Statement


Consider fields of 1.4e5 N/C and 2.7 T within a velocity selector. If the charge then exits and encounters a field of 1.4 T and radius of 2.4 mm within the mass spectrometer, what would be the mass to charge ratio of this ion?

Homework Equations


v = E/B
m = qrB/V[/B]

q = 1.6 x 10 ^-19C
r = 2.4 x 10^-3 m
B = 1.4 T

The Attempt at a Solution



I got 51851 m/s for v

and my answer came out way off when I plugged it in for m.

I have the answer but when I try to do it myself. I get the wrong answer.
 
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The exercise asks for m/q, not for m. What did you get ?
And what exactly do you mean when you say 'I get the wrong answer' ?

By the way: you got 5.2 x 104 m/s, not 51851 m/s : you can't achieve five digit accuracy when all you're given is two digit numbers! But v wasn't wanted.
(However, when you work out this exercise with the given numbers in the expression for m/q, you do end up to within 1 promille of m/q of a known particle...what a coincidence!)
 
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