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Mass-Volume stoichiometry

  1. Oct 8, 2012 #1
    1. The problem statement, all variables and given/known data
    How many millilitres of oxygen gas are released from heating 5.00 grams of calcium chlorate?


    2. Relevant equations

    Ca(ClO3)2→CaCl2+3O2

    Ca(ClO3)2 =207.7g
    CaCl2=110.98g
    O2=22.4 g/L
    Mole ratio= 3mol O2/1mol Ca(Clo3)2

    3. The attempt at a solution
    This is what I have but it is not coming out right and I just cant figure out where im going wrong. I am having trouble with these kinds of problems.

    (207.7 g/ 1 mol Ca(Clo3)2) X (1mol Ca(Clo3)2/3 mol O2) X (22.4 L O2/ 1 mol O2)= 1550.8
    (this cant be right the answer is supposed to be 1620)
     
    Last edited: Oct 8, 2012
  2. jcsd
  3. Oct 8, 2012 #2

    AGNuke

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    Gold Member

    Moles of Calcium Chlorate (Given Mass / Molar Mass)* Moles of dioxygen per mole of Calcium Chlorate (3) * Volume of 1 mole dioxygen (22.4 L / mol).

    The answer is approximately 1617. (1620 if you approximately calculate it manually)
     
  4. Oct 8, 2012 #3
    I now see where I went wrong!! thank you :)
     
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