M P
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I bet you smiling now ;)
before I go further -55.74 - 20.06j + 0.25 V40 - 0.05 j V40 ?gneill said:
I'm not seeing where that's coming from. Sorry.M P said:before I go further -55.74 - 20.06j + 0.25 V40 - 0.05 j V40 ?
That'll work. Or,Ebies said:I3(-Z3) - V2 - Z5(I3-I2) = 0...Eq 3 new and revised eq 3
While you can use either direction to achieve valid equations, you must be consistent in your choice. Once you've made a selection of current direction for a mesh you must not change it, otherwise where loops "touch" the current sums through the shared components will be compromised.Ebies said:when using mesh analysis to determine the voltage drop direction, do you use conventional current flow or do you use the clockwise current you chosen at the beginning when assigned your clockwise mesh currents...? I am asking so I know when to add or subtract when doing the "KVL" walk... I am a bit confused about what the sign needs to be when walking the "KVL" loop and you encounter components... spent a lot of time going through my books and watching online tutorials and its confused me even more now