(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two resistors connected in series have an equivalent resistance of 744.7 Ω. When they are connected in parallel, their equivalent resistance is 130.4 Ω. Find the resistance of each resistor.

Ω (small resistance)

Ω (large resistance)

2. Relevant equations

Req = R1 + R2 for Series.

1/Req = 1/R1 + 1/R2 for Parallel.

3. The attempt at a solution

Ok, so I began by solving one for R1 and plugging it into the other...

If I solve the first one I get R1 = Req - R2. Let's call Req, Reqs for Equivalent Resistance in series. Lets call Reqp the Equivalent Resistance in parallel.

So I plug into the other one:

1/Reqp = 1/ (Reqs - R2) + 1/R2

Messing around I am able to get:

R2Reqs - R2^2 = Reqs*Reqp However when I graph if there is no sign change.... I've done it a few times so I don't think it's my algebra.

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# Homework Help: Math problem with Resistors

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