(Mathematical Physics) Mass on four elastic rods

AI Thread Summary
The discussion revolves around a physics problem involving a 10^4 kg mass placed on four elastic rods arranged in a square configuration. The rods, made of copper and steel, need to be analyzed for their contraction under the weight of the mass and how temperature affects their height. The initial assumption is that all rods contract equally, which raises contradictions regarding weight distribution. The problem also seeks to determine the temperature change required for only two rods to support the entire mass. Participants are looking for guidance on solving these aspects of the problem.
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Homework Statement


In a gravitational detector we put a mass of 10^4 kg onto four rods, which are located at the angles of a square. The rods are 25 cm high with S = 3cm^2, two of them are made of copper, two of steele and they are situated on opposite sides. The top surfaces of rods are polished to the exactly the same height, the bottom side of the test mass is polished with same precision.
A) For how much do the rods contract when we carefully place the test mass onto them, so that its center of mass is exactly above the center of the square?
B) How does the height of rods depend on the temperature?
How much does the temperature need to change so that only two rods would carry entire test mass?
E(Cu)=8*10^10 N/m^2, E(steel)=2*10^11 N/m^2, the coefficients of linear thermal expansion are 17*10^(-6) K^(-1) for copper and 12*10^(-6) K^(-1) for steel.


The Attempt at a Solution


http://img638.imageshack.us/img638/8550/mafinaloga1.jpg
I think my attempt is not correct. I started by supposing that all rods contract to the same lenght.
This is a problem from an old exam (Mathematical Physics) so I don't have the solution. Any help would be appreciated.
 
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It would seem the rods must contract the same amount (for the weight not the heat) since otherwise to rods carry all the weight thus the others don't contract thus they do carry weight which is a contradiction.
 
Ok. How about the rest of my solution? (I'm sorry I had to post a picture, but I'm no good at typing equations and this was easier.)
 
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