Matrix representation of a quantum system

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Homework Help Overview

The discussion revolves around finding the matrix representations of the spin operators Sx, Sy, and Sz in quantum mechanics, specifically focusing on the implications of different kets and their representations.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the representation of the spin operator Sx and question how the ket |±> affects the matrix representation. There is a discussion about the Dirac notation and the distinction between different kets.

Discussion Status

The conversation is ongoing, with participants seeking clarification on the relationship between kets and their matrix representations. Some guidance has been offered regarding the need to consider the specific kets involved in the calculations.

Contextual Notes

There is mention of confusion regarding the effects of different kets on the matrix representation, and the discussion includes assumptions about the representation of kets in vector form.

whatisgoingon
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Homework Statement


I have to find the matrix system of Sx, Sy , and Sz using the given information:
190899[/ATTACH]']
MR5aRwH.jpg

Homework Equations

The Attempt at a Solution


for attempting Sx:
Ignoring the ket at the bottom, I would get Sx|+> = +ħ/2[[0,1],[1,0]]
but my question here is, does the ket at the bottom(the |±>x = 1/√2 [|+> ± |->] affect the matrix?
because the matrix form of the ket will be 1/√2([1,1]).
With that said, would I have to insert that into the Sx equation? Giving me the matrix representation of 190901[/ATTACH]']
7qaYfVU.jpg
 

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whatisgoingon said:
Ignoring the ket at the bottom, I would get Sx|+> = +ħ/2[[0,1],[1,0]]
That doesn't make sense. The result of an operator on a ket is a ket, so it can be represented as a vector, not a matrix. And how can you obtain that result without considering "the ket at the bottom?"

What is the Dirac representation of a matrix element?
 
DrClaude said:
That doesn't make sense. The result of an operator on a ket is a ket, so it can be represented as a vector, not a matrix.
whoops, I meant Sx is represented as ħ/2 [[0,1],[1,0]].
DrClaude said:
And how can you obtain that result without considering "the ket at the bottom?
I was under the assumption that the ket |+> = [1,0] and that the ket at the bottom didn't affect it. From your response I guess, it does affect it.

Also isn't the dirac representation just the bra and ket? <+|A|+>
 
whatisgoingon said:
whoops, I meant Sx is represented as ħ/2 [[0,1],[1,0]].
Ok. But, still, how did you get that matrix?

whatisgoingon said:
I was under the assumption that the ket |+> = [1,0] and that the ket at the bottom didn't affect it. From your response I guess, it does affect it.
You have to distinguish between ##| \pm \rangle## and ##| \pm \rangle_x##

whatisgoingon said:
Also isn't the dirac representation just the bra and ket?
Yes. What is a single matrix element of the representation of an operator in bracket notation?
 

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