Matrix representation of a quantum system

AI Thread Summary
The discussion focuses on finding the matrix representations of the spin operators Sx, Sy, and Sz in quantum mechanics. The user initially attempts to derive the matrix for Sx but questions whether the ket notation affects the matrix representation. It is clarified that the result of an operator acting on a ket yields another ket, which can be represented as a vector, not a matrix. The distinction between different ket notations, such as |+> and |±>_x, is emphasized as crucial for accurate calculations. Overall, understanding the relationship between kets and their matrix representations is essential for solving the problem correctly.
whatisgoingon
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Homework Statement


I have to find the matrix system of Sx, Sy , and Sz using the given information:
190899[/ATTACH]']
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Homework Equations

The Attempt at a Solution


for attempting Sx:
Ignoring the ket at the bottom, I would get Sx|+> = +ħ/2[[0,1],[1,0]]
but my question here is, does the ket at the bottom(the |±>x = 1/√2 [|+> ± |->] affect the matrix?
because the matrix form of the ket will be 1/√2([1,1]).
With that said, would I have to insert that into the Sx equation? Giving me the matrix representation of 190901[/ATTACH]']
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whatisgoingon said:
Ignoring the ket at the bottom, I would get Sx|+> = +ħ/2[[0,1],[1,0]]
That doesn't make sense. The result of an operator on a ket is a ket, so it can be represented as a vector, not a matrix. And how can you obtain that result without considering "the ket at the bottom?"

What is the Dirac representation of a matrix element?
 
DrClaude said:
That doesn't make sense. The result of an operator on a ket is a ket, so it can be represented as a vector, not a matrix.
whoops, I meant Sx is represented as ħ/2 [[0,1],[1,0]].
DrClaude said:
And how can you obtain that result without considering "the ket at the bottom?
I was under the assumption that the ket |+> = [1,0] and that the ket at the bottom didn't affect it. From your response I guess, it does affect it.

Also isn't the dirac representation just the bra and ket? <+|A|+>
 
whatisgoingon said:
whoops, I meant Sx is represented as ħ/2 [[0,1],[1,0]].
Ok. But, still, how did you get that matrix?

whatisgoingon said:
I was under the assumption that the ket |+> = [1,0] and that the ket at the bottom didn't affect it. From your response I guess, it does affect it.
You have to distinguish between ##| \pm \rangle## and ##| \pm \rangle_x##

whatisgoingon said:
Also isn't the dirac representation just the bra and ket?
Yes. What is a single matrix element of the representation of an operator in bracket notation?
 
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