Max Magnetic Force Experienced by Electrons Accelerated at 19 kV

AI Thread Summary
Electrons in a television set are accelerated through a potential difference of 19 kV, gaining kinetic energy. The maximum magnetic force experienced by the electrons, when passing through a 0.29 T magnetic field, can be calculated using the relationship between kinetic energy and potential difference. The Work-Energy Theorem states that 1/2 mv^2 equals qV, allowing for the calculation of the electron's velocity. Once the velocity is determined, it can be used to find the magnetic force using the formula B = F/(qv). Understanding this relationship is crucial for solving the problem effectively.
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In a television set, electrons are accelerated from rest through a potential difference of 19 kV. The electrons then pass through a 0.29 T magnetic field that deflects them to the appropriate spot on the screen. Find the magnitude of the maximum magnetic force that an electron can experience.

Here are my thoughts so far... this is all i know...
B=F/(qv)
B=.29
19kV=19000 V
I need to find the velocity of the electron to solve for F, the only problem is...
I HAVE NO IDEA HOW TO RELATE POTENTIAL DIFFERENCE TO VELOCITY! please help. THANKS.
 
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Electrons gain energy when the are accelerated. Once they escape the influence which was accelarates them, the energy is purely kinetic.
 
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i don't understand still...do i have to use the kinetic energy theorom? and if i do what do i plug into it? thanks
 
We know that the maximum magnetic force occurs when velocity is maximum.

The electron is being accelerated through a potential difference. By the Work-Energy Theorem

1/2 mv^2 = qV
When all the energy the electron gains from the potential difference goes to kinetic energy, its velocity is maximized.

Solve for velocity. Does that help?
 
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