Max Speed for 1500 kg Car on 90 m Curve

AI Thread Summary
The maximum speed for a 1500 kg car rounding a 90 m curve on a flat road, with a coefficient of static friction of 0.5, is 21 m/s. The solution involves equating centripetal force to the force of friction and solving for velocity. The discussion emphasizes the importance of providing specific questions and prior attempts when seeking help. The correct answer has been confirmed as 21 m/s. Understanding the relationship between centripetal force and friction is crucial for solving such problems.
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what is the maximum speed at which a 1500 kg car can round a curve on a flat road if the radius of the curve is 90 m and the coefficient of static friction is 0.5? (ans. 21 m/s) thank you...
 
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In order to get help, you need to post what you have tried, and specific questions about the point where you got stuck.
 
21 m/s is the correct answer.
 
i figured it out...thanks

for anyone that cares...

centripetal force = force of friction, solve for v...
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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