Maxima and Minima of tan(sinx + sin3x) on (-pi,pi)

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Homework Statement


Find the maxima and minima of the function f(x)=tan(sinx + sin3x) on the interval (-pi,pi)


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The Attempt at a Solution


I found the derivative as sec^2x (sinx +sin3x) (cosx + cos3x) and when i set it equal to zero i found critical points at Sin=pi/2, and cos=pi/2
 
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Your derivative is incorrect. The derivative of sin(3x) is not cos(3x)...
 
Wait i typed that part wrong. i had derivative of sin(3x) as 3Cos(3x)
 
Good, so your derivative is

\frac{\cos(x)+3\cos(3x)}{\cos^2(\sin(x)+\sin(3x))}

This can only become zero if \cos(x)+3\cos(3x). So you'll need to solve the equation \cos(x)=-3\cos(3x). I believe there will be infinitly many solutions to this, but I'm not sure...
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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