Maximizing Pipe Length: Solving a Horizontal Carry Dilemma

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Homework Help Overview

The problem involves determining the maximum length of a steel pipe that can be carried horizontally around a right-angle turn between two hallways of different widths: 9ft and 6ft. Participants are exploring geometric and calculus-based approaches to relate the dimensions and angles involved in the scenario.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants are attempting to relate the geometry of the problem to calculus by deriving a function that represents the length of the pipe in relation to the angle of the turn. Some are questioning the validity of their geometric interpretations and the assumptions made about the dimensions.

Discussion Status

There is ongoing exploration of different methods to approach the problem, including geometric breakdowns and calculus applications. Some participants have provided insights into how to formulate the problem mathematically, while others express confusion about the wording and setup of the problem.

Contextual Notes

Participants note that the problem's wording may lead to misunderstandings regarding the setup, and there is a suggestion that the relationship between the pipe length and the angles could be explored using trigonometric identities.

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A steel pipe is being carried horizontally down a hallway that is 9ft wide. At the end of the hallway there is a right turn into a hallway that is 6ft wide. What is the length of the longest pipe that can be carried horizontally around the corner? (Hint: minimize the line)

I have looked at this problem and tried many ways to solve it. I cannot think of a way to relate my information to make a derivable function.

I did make a bunch of triangles and using geometry I'm pretty sure the answer is 21ft but man if I can't do this with calculus. Help!
 
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Slimjimjohnso said:
A steel pipe is being carried horizontally down a hallway that is 9ft wide. At the end of the hallway there is a right turn into a hallway that is 6ft wide. What is the length of the longest pipe that can be carried horizontally around the corner? (Hint: minimize the line)

I have looked at this problem and tried many ways to solve it. I cannot think of a way to relate my information to make a derivable function.

I did make a bunch of triangles and using geometry I'm pretty sure the answer is 21ft but man if I can't do this with calculus. Help!

21ft? That's longer than both hallway's are wide put together.
 
Imagine an L shaped hallway. The short part of the L is 9ft the long part is 6ft. If you drag one side along the 9ft part around the corner into the 6ft part why couldn't it be 21ft?

I would show the picture I have drawn but I am on my phone at work and don't have a way to post it here.
 
Slimjimjohnso said:
http://lh4.ggpht.com/_KCqQzK7M3K4/TEJcWqbbWxI/AAAAAAAAAAU/lyWzaS6BdFI/s400/2010-07-17 20.27.40.jpg

There that should be the picture with my triangles.

I broke the left half into 3 right trianlgs joined by a equilatteral. I solved for the hypotenuse of one and since its part of a bigger triangle all sides are even. I then solved the big triangle consisting of both hallways for its hypotenuse getting 21.

I need help doing this the calc way. Any direction would be awesome.

The problem states that the steel pipe begins by being carried horizontally down a hallway that is 9 ft wide... sorry but this is just a horrible wording of the question if that diagram was the setup in mind.
 
The problem and picture is directly off of my homework.

I added the lines in between the L shaped hallway. But the line is the hypotenuse of a bigger triangle. The only thing I can think to relate the problem to calculus is through some sort of trig identities.
 
Break the length of the pipe into two pieces, x1 and x2, where x1 is the portion that's in the 9' hallway and x2 is the portion in the 6' hallway. Relate these lengths to the angle θ and the width of the respective hallway. You'll get an expression for the total length of the pipe L=x1+x2 as a function of θ. That's the function you want to minimize.
 
Thank you very much for your help.

I ended up with

I took cos(theta)=9/a and sin(theta)=6/b
To get my function

L(theta)=9sec(theta)+6csc(theta)
 

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