Maximizing Speed on a Curved Road: Calculating Safe Speed with Varying Radii

  • Thread starter Thread starter Alexs45
  • Start date Start date
  • Tags Tags
    Maximum Speed
AI Thread Summary
The discussion highlights confusion regarding the problem statement, specifically the mention of two different radii for the same curved road. The first radius is given as 50 m, while the second radius is stated as 200 m (2.00 x 10^2). Participants emphasize the need for clarity in problem descriptions to avoid misunderstandings. The calculation of maximum safe speed for negotiating a curve depends on the radius and the coefficient of static friction. Accurate information is crucial for solving physics problems related to vehicle dynamics on curved paths.
Alexs45
Messages
7
Reaction score
0
A car enters a horizontal, curved roadbed of radius 50 m. The coefficient of static friction between the tires and the roadbed is 0.20. What is the maximum speed with which the car can safely negoitate the curve if the radius of the curve 2.00 x 10^2?


please help
 
Physics news on Phys.org
Start by reading the problem carefully. It makes no sense to say "roadbed of radius 50 m" and then say "the radius of the curve 2.00 x 10^2".
 
that confused me also. two radii for one object.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top