Maximum Force for Block on Bracket Friction?

AI Thread Summary
The discussion revolves around calculating the maximum force that can be applied to a block resting on a bracket without causing it to slide, as well as determining the acceleration of the bracket. The maximum static friction force was calculated as 39.24N, derived from the block's weight and the coefficient of static friction. However, participants noted that this value represents the maximum friction force, not the applied force, especially since the system is accelerating. To find the acceleration of the bracket, Newton's second law must be applied to both the block and the entire system, leading to a more complex interaction than initially assumed. The key takeaway is that the maximum applied force must account for the system's acceleration, not just the static friction limit.
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Homework Statement


A 10kg block is resting on a 5kg bracket, which rests on a frictionless surface. The coef. of static and kinetic friction between the block and bracket are .4 and .3, respectively. Find out a) the max force that can be applied to the block without the block sliding on the bracket and b) the acceleration of the 5kg bracket.

http://img114.imageshack.us/img114/1958/56qe9.jpg

Homework Equations



Fnet = m * a

The Attempt at a Solution



This seems like a very simple question but I'm just having an issue with it (plus the book calls it a "challenging" problem so it just seems too easy).

Finding a) was pretty simple, just do 10 * .4 * 9.81 (Normal Force * \muk). I came up with 39.24N as the answer.

To find b I thought it would just have to apply Newton's second law.

39.24N = (5kg + 10kg) * a
a = 2.62m/s

But since this seemed too easy so I thought that I was wrong. Since the bracket exerts a frictional force on the block, do I have to include the force of the block on the bracket as given by Newton's third law? That seemed logical to me but then it would obviously negate the force of the string which would mean no acceleration, and it seems extremely obvious that there would be acceleration.

Any help would be great, thanks.
 
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Proximity said:
Finding a) was pretty simple, just do 10 * .4 * 9.81 (Normal Force * \muk). I came up with 39.24N as the answer.
What you found is the maximum value of static friction, which is not the same thing as the applied force F. (If F simply equaled the max friction force then the block would be in equilibrium.)

So it's not that simple. Apply Newton's 2nd law to the block and to the system as a whole.
 
That is what F equals though, isn't it? The question asks the max force that can be applied to the block so it doesn't slide. The max force that the static friction can apply is 39.24N, and so the max force on the string that can be applied is also 39.24N.
 
Proximity said:
That is what F equals though, isn't it?
No.
The question asks the max force that can be applied to the block so it doesn't slide. The max force that the static friction can apply is 39.24N, and so the max force on the string that can be applied is also 39.24N.
That would be true if it wasn't accelerating. But it is. Apply Newton's 2nd law.
 
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