Maximum Height of Lighter Object in Pulley System - Homework Solution

AI Thread Summary
The discussion revolves around calculating the maximum height reached by a lighter object in a pulley system involving two masses, 3.2kg and 2.2kg, initially 1.80m above the ground. The user determined the acceleration to be 1.8m/s² and calculated the time it took for the heavier mass to hit the ground, which was 1.4 seconds. Using this time, they found the velocity of the lighter object to be 2.56 m/s, but expressed uncertainty about their calculations for maximum height. They attempted to apply the kinematic equation but questioned whether they considered all factors correctly. The conversation seeks clarification on the accuracy of their approach and calculations.
joseg707
Messages
32
Reaction score
0

Homework Statement


Two masses, 3.2kg and 2.2kg are each initially 1.80m above the ground, and the massless and frictionless pulley is 4.8m above the ground. What maximum height dies the lighter object reach after the system is released? Assume it doesn't hit the pulley.


Homework Equations


F=ma
y=yo+vo+1/2at2

The Attempt at a Solution


I solved for acceleration by using F=ma and got 1.8m/s2.
I then solved for the velocity of the lighter object when the heavier object hit the ground by solving for the time it took for the heavier object to hit the ground and used that time to find the velocity

-1.8=-0.9t2
t=1.4

v=1.8*1.4
v=2.56

After finding the velocity I used that to find the maximum height.

y=2.56t-4.9t2
t=0, 0.522

0.522/2
t=0.261

y=3.6+2.56t-4.9t2
y=3.93333

I think I didn't take something into account or I used the wrong equation completely. Can someone help me?
 
Physics news on Phys.org
Looks good to me.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top