Maximum Load question given Safety factor

Thread starter bad at math gu
Start date Jan 15, 2014
Tags

Load Maximum Safety

AI Thread Summary

The ultimate strength of the round steel rod is 620.000 MPa, and with a required safety factor of 3.000, the maximum permissible load can be calculated by dividing the ultimate strength by the safety factor. The diameter of the rod is 3.000 cm, which allows for the calculation of the cross-sectional area using the formula for the area of a circle. The maximum load is then determined by multiplying the allowable stress by the cross-sectional area. The user initially sought help but later indicated they solved the problem independently. This illustrates the importance of understanding safety factors in engineering applications.

Jan 15, 2014

bad at math gu

Could i get some help with this one please

The ultimate strength of a round steel rod is 620.000 MPa. If a factor of safety of 3.000 is required, what is the maximum permissible load for the rod if it has a diameter of 3.000 cm?

Physics news on Phys.org

Jan 15, 2014

consciousness

Show your work

Jan 15, 2014

bad at math gu

:D nvm i just got it

Thread 'Errors and significant figures'

I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...

View full post »

Thread 'A cylinder connected to a hanging mass'

Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

View full post »

Thread 'Explain this asphalt sheen'

This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is The second part of the problem is exactly why you get this affect. And one more spoiler:

View full post »