Maximum of a trigonometric function

NaturePaper
Messages
70
Reaction score
0
This is related to my previous https://www.physicsforums.com/showthread.php?t=398964". I am having trouble to get the maximum of the following trigonometric function:

<br /> <br /> \cos^m\theta_1(c\cos^n\theta_2+s\sin^n\theta_2)+\sin^m\theta_1 ( c\sin^n\theta_2+s\cos^n\theta_2)<br /> <br />

Here m,n\ge2 \mbox{ are fixed positive integers and } c,s are fixed positive reals with c^2+s^2=1. The maximum is to be carried out w.r.t. \theta_1,\theta_2 in the range 0\le\theta_1,\theta_2\le\frac{\pi}{2} In my trying, I got the maximum to be max(c,s), but I fear may be I have done some mistake. I got the result by differentiating w.r.t. \theta_1,\theta_2 and vanishing them...but I have ignored the case when \cos\theta_1\cos\theta_2\sin\theta_1\sin\theta_2\ne0. Can anybody help me, please.

Can I say that the function is all time differentiable within its closed and compact domain (the rectangle), the maximum should be attained on boundary?
 
Last edited by a moderator:
Physics news on Phys.org
Plotting in mathematica with different values, I can not find an exception.

But the reasoning of closed, compact domain can not be applied, because though the domain is convex, the function is itself not a convex one. However, we can split the domain such that in each part, the function remains monotonic.
 
Oh, finally I got an answer to this question...the proof is a handy one (according to me, of course!:smile:). The answer is indeed correct.

Since \cos\theta_1\cos\theta_2\sin\theta_1\sin\theta_2\ne0, \cos\theta_1,\cos\theta_2,\sin\theta_1,\sin\theta_2&lt;1.
so

\cos^m\theta_1(c\cos^n\theta_2+s\sin^n\theta_2)+<br /> \sin^m\theta_1 ( c\sin^n\theta_2+s\cos^n\theta_2)

\le <br /> \cos^2\theta_1(c\cos^2\theta_2+s\sin^2\theta_2)+<br /> \sin^2\theta_1 ( c\sin^2\theta_2+s\cos^2\theta_2)

\le\frac{c+s}{2}

&lt;\max\{c,s\}

Regards.
 
Last edited:
Back
Top