One often stated advantage of ethanol/water as a recrystallization solvent is that the mixture behaves like ethanol at reflux and like water at room temperature or below. Assuming that 24 mL of the solvent is used per 1 g of crude product and recrystallization and recovery of the product is done at room temperature, what is the maximum percent recovery that can be achieved?
The Attempt at a Solution
I thought perhaps we could convert 24 mL of solvent into 24 g of solvent using water's density as a conversion factor (1.00 g/mL) since the solvent acts like water during recrystallization and recovery in this question. Then I took the ratio of crude product to solvent:
1g product / 24g solvent * 100% = 4.2% lost
Therefore 100% - 4.2% = 95.8% recovery.
Not only do I not have confidence that this is correct, but I also don't know why this calculation makes sense, if at all.
Thanks a lot for any help!