Maximum Speed of a Mass on a Spring with Given Mass and Spring Constant

AI Thread Summary
A 300 g mass on a frictionless surface vibrates on a spring with a constant of 45 N/m and a maximum displacement of 8.0 cm. To find the maximum speed, the spring force is calculated using F_spring = kx, resulting in 3.6 N. This force is then used to determine acceleration (a = F/m), yielding an acceleration of 12 m/s². The maximum speed is calculated using the equation Vf² = Vi² + 2ad, leading to a maximum speed of 1.4 m/s. The discussion confirms that maximum displacement refers to the distance from the uncompressed position to maximum compression.
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Homework Statement


a 300 g mass vibrates at the end of a horizontal spring along a frictionless surface. if the spring constant is 45N/m, and the maximum displacement of the mass is 8.0cm, what is the maximum speed of the mass?


Homework Equations



g=Gm/r^2

The Attempt at a Solution


do i rearrange the formula to solve for m. so it becomes m=r^2(g)/G. that only gives me the mass tho. how do i solve for the speed??
 
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I don't even know what you're doin.

Find the acceleration with F_spring=kx and F=ma.

When is the spring traveling the fastest? You should use (or combine) 3 equations to get your answer. I gave you 2.
 
ok so,
Fspring= 45N/m(0.08m) whick is 3.6N. then arrange f=ma to solve for a, which is a=3.6N/0.3Kg, so the a is 12. then do i use the formula Vf^2=Vi^2 + 2ad. so,i would square root (2)(12)(0.08) to get 1.4 m/s as the maximum speed?
 
if "maximum displacement" means the distance from where the spring is uncompressed, to it's maximum compression.. then yes that's right.
 
Thank you so much :)
 
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