Show that the maximum area of a triangle corresponds to the triangle being equilateral. I start by making y the height of the triangle and x a leg. We have two formulas (for area) A = xy/2 A = sqrt(s(s-a)(s-b)(s-x)) I'm thinking that in order to find the maximum, we must make dA/dx = 0 and show that x=a=b . Any suggestions on how to do this? Forgive me if this is really easy, I've been out of school for some time and have forgotten alot--trying to learn again.