Maximum weight that helium balloon can lift

AI Thread Summary
To determine the maximum weight a helium balloon can lift, the density of helium and the volume of the balloon must be considered. The balloon's volume can be calculated using the formula for the volume of a sphere, which is V = (4/3)πr³. The buoyant force can then be found using the equation Fb = pgV, where p is the density of air and g is the acceleration due to gravity. After calculating the buoyant force, subtract the weight of the balloon itself to find the maximum lift capacity. Properly applying the density values is crucial for accurate results.
Raiden9
Messages
10
Reaction score
0
Hi. I have been trying to do this question for about an hour now...

A 0.12 kg balloon is filled with helium (density-0.179). If the balloon is a sphere with a radius of 5.2m what is the maximum weight it can lift.

I tried using the P=M/V then Fb=pgV...No luck...Help..
 
Physics news on Phys.org
Oh dear...The answer was I forgot to use the density...Silly me..
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top