Maximum work obtained by mixing 2 gases

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Homework Help Overview

The problem involves two boxes containing identical ideal gases with the same adiabatic index and initial temperature but different volumes. The objective is to find the maximum mechanical work obtainable when these gases are brought together.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to understand how to calculate the work done by the gases during mixing, considering their different pressures due to volume differences. They question whether to assume adiabatic isolation and constant temperature, and express uncertainty about relating entropy variation to work done.
  • Some participants suggest that the problem may involve an insulated partition between the gases, leading to adiabatic reversible expansion, and they inquire about the final pressure in one of the chambers.
  • Others propose discussing the expression for the given answer to explore its derivation, noting the presence of gamma and volume ratios.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem setup and the implications for calculating work. Some guidance has been offered regarding the assumption of an insulated partition, but no consensus has been reached on the exact approach or solution.

Contextual Notes

Participants are working without access to reference materials, which may limit their ability to verify the given answer or explore the problem further. There is also uncertainty regarding the assumptions about the system's isolation and temperature conditions.

superduper
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Homework Statement


2 boxes containing the same number of moles of 2 ideal identical gases with the same adiabatic index (this is given as gamma), at the same initial temperature Ti but with different volumes, V1 and V2 are brought together. Find the maximum mechanical work that can be obtained.

Homework Equations

The Attempt at a Solution


If the gases have all the parameters identical but the volumes, that means that they also have different pressures, so when we are mixing them, the gas with the higher pressure will do work on the gas with lower pressure. However, I have no idea how to calculate this work and the answer given is a big messy expression. It dosent say anything about the recipients being adibatically isolated, but I guess I have to assume that? The temperature will be constant? I think I should calculate the variation of entropy for the system and then relate this to the first principle to get the work done, but I have no idea how to do that.
 
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Hi again. Welcome to Physics Forums.

I don't think the problem intends for you to assume that the gases are intimately mixed. I think it intends for you to assume that there is an insulated partition separating the two gases, and to find the maximum amount of work that they can do on the partition. If I'm right, my solution to this problem should match the given answer. Do you want me to reveal my solution so that you can compare it with the given answer?

If my interpretation is correct, then in both chambers, an adiabatic reversible expansion occurs. So, in each chamber, PVν=constant. Let's focus on chamber 1. Let ##P_0## represent the initial pressure nRT/V1, let P represent the final pressure when the pressures on both sides of the partition have equilibrated, and let ##V_{1f}## represent the final volume. In terms of ##P_0##, V1, and ##V_{1f}##, what is the final pressure P in chamber 1?

Chet
 
Last edited:
Maybe you can provide the expression for the given answer, and we can try to determine how it was derived.

Did the expression have a bunch of gamma's and volume ratios in it?
 
Does it look anything like this:

$$W=nRT_i\left[2-\left(\frac{1+(V_2/V_1)^{\frac{\gamma-1}{\gamma}}}{1+(V2/V_1)}\right)^{\gamma-1}-\left(\frac{1+(V_1/V_2)^{\frac{\gamma-1}{\gamma}}}{1+(V1/V_2)}\right)^{\gamma-1}\right]$$
 
Sorry for the late response, but I'm away from uni and don't have the book at my disposal to see if that's the exact answer, but, yes, I remeber it has a bunch of gammas and volume ratios involved
 
superduper said:
Sorry for the late response, but I'm away from uni and don't have the book at my disposal to see if that's the exact answer, but, yes, I remeber it has a bunch of gammas and volume ratios involved
So, where do you want to go from here? How would you like me to help you?
 

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