kendro
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Hi. I have a problem about rolling motion. Suppose that I have a large hollow cylinder. A smaller solid cylinder is embedded inside the larger hollow cylinder.
http://www.geocities.com/andre_pradhana/cylinderkendro2.JPG
When I positioned the cylinder on a flat ramp like the picture below:
http://www.geocities.com/andre_pradhana/cylinderkendro5.JPG
The cylinder will start oscillating back and forth as the weight of the extra mass provide a torque, causing the cylinder to rotate.
http://www.geocities.com/andre_pradhana/cylinderkendro4.JPG
My question is, suppose that the value of \Beta initially was \pi/4 before the cylinder is released and start rolling, how can I calculate the time it takes before the \theta reaches a value of \pi (when the extra mass is directly above the point P)?
Suppose that the torque caused by the weight of the smaller cylinder is M_1gxsin\theta and the Moment of Inertia is: M_2R_2+0.5 M_1r_1^2. I can then figured out the equation for angular acceleration, which is: \displaystyle{\frac{M_1gxsin\theta}{ M_2R_2+0.5 M_1r_1^2}}
However, what I don’t know any formula that relates \theta as a function of time. How can I find the time it takes for the smaller cylinder to move from an initial displacement of \pi/4 befor the cylinder is released until the value of angular displacement is \pi’ i.e. when it’s directly above the point P, assuming that there is NO friction.
I know that there’s a formula relating \alpha\times\theta:
\omega_t^2=\omega_0^2+2\alpha\theta
Does it mean that if I integrate:
\int_ {\pi/4}^{\pi} \alpha d\theta
Will I get the value of 0.5\times\omega_t^2 when \theta is \pi? (with the assumption that the value of \omega_0 initially is 0 rad/s)? From dimensional analysis, I know that integrating that the integration will give me the value of constant\times\omega^2
If that’s true, then I can figured out the average angular acceleration to calculate the time it takes for the extra mass to travel from \pi/4 to \pi.
Is there another approach to solve this problem?
Thank you very much for your help...
http://www.geocities.com/andre_pradhana/cylinderkendro2.JPG
When I positioned the cylinder on a flat ramp like the picture below:
http://www.geocities.com/andre_pradhana/cylinderkendro5.JPG
The cylinder will start oscillating back and forth as the weight of the extra mass provide a torque, causing the cylinder to rotate.
http://www.geocities.com/andre_pradhana/cylinderkendro4.JPG
My question is, suppose that the value of \Beta initially was \pi/4 before the cylinder is released and start rolling, how can I calculate the time it takes before the \theta reaches a value of \pi (when the extra mass is directly above the point P)?
Suppose that the torque caused by the weight of the smaller cylinder is M_1gxsin\theta and the Moment of Inertia is: M_2R_2+0.5 M_1r_1^2. I can then figured out the equation for angular acceleration, which is: \displaystyle{\frac{M_1gxsin\theta}{ M_2R_2+0.5 M_1r_1^2}}
However, what I don’t know any formula that relates \theta as a function of time. How can I find the time it takes for the smaller cylinder to move from an initial displacement of \pi/4 befor the cylinder is released until the value of angular displacement is \pi’ i.e. when it’s directly above the point P, assuming that there is NO friction.
I know that there’s a formula relating \alpha\times\theta:
\omega_t^2=\omega_0^2+2\alpha\theta
Does it mean that if I integrate:
\int_ {\pi/4}^{\pi} \alpha d\theta
Will I get the value of 0.5\times\omega_t^2 when \theta is \pi? (with the assumption that the value of \omega_0 initially is 0 rad/s)? From dimensional analysis, I know that integrating that the integration will give me the value of constant\times\omega^2
If that’s true, then I can figured out the average angular acceleration to calculate the time it takes for the extra mass to travel from \pi/4 to \pi.
Is there another approach to solve this problem?
Thank you very much for your help...