I Meaning of "c number equations"?

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The term "c-number equations" in quantum optics refers to classical or commuting numbers, which are ordinary numbers rather than operators. This distinction is important as it differentiates between classical and quantum representations in equations. The discussion clarifies that "c" does not relate to complex values or the speed of light but specifically denotes classical numbers. The historical context includes a contrast with "q-numbers," which represent quantum operators. Understanding this terminology is essential for grasping concepts in quantum optics.
TheCanadian
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I keep reading authors refer to "c number equations" in different texts on quantum optics. Perhaps I am missing something very obvious, but what exactly does this mean? Does it mean complex-valued equations? Does it have to do with the speed of light? Does c describe the number of equations being evaluated?

Here are a couple examples:

1st paragraph of page 190

Section 6.2 in this text

I've just seen the term used in different contexts yet never had its meaning clarified. Maybe it's so blatantly obvious that it does not require explanation. But nevertheless, I am looking for one.
 
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The term "c-number" refers to so-called 'classical' or 'commuting' numbers i.e. they are just ordinary numbers and not operators (there was a time when operators were referred to as "q-numbers" - the "q" ostensibly meaning "quantum").
 
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Fightfish said:
The term "c-number" refers to so-called 'classical' or 'commuting' numbers i.e. they are just ordinary numbers and not operators (there was a time when operators were referred to as "q-numbers" - the "q" ostensibly meaning "quantum").

Interesting! Thank you for the help.
 
So I know that electrons are fundamental, there's no 'material' that makes them up, it's like talking about a colour itself rather than a car or a flower. Now protons and neutrons and quarks and whatever other stuff is there fundamentally, I want someone to kind of teach me these, I have a lot of questions that books might not give the answer in the way I understand. Thanks
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