Measuring of electrode potential.

AI Thread Summary
The discussion centers on the functionality of a voltmeter in measuring potential difference across two half-cells in an electrochemical setup. There is a common misconception that the high resistance of the voltmeter creates an open circuit, preventing electron flow and thus inhibiting the redox reactions in the half-cells. However, it is clarified that the voltmeter does not leave the circuit open; instead, it closes the circuit and measures the current flowing through a known resistance, displaying the potential difference according to the formula V=RI. The conversation emphasizes that understanding how a voltmeter operates is fundamentally a physics question, highlighting the relationship between potential difference, charge, and circuit closure. The role of high resistance is acknowledged, but it is noted that the voltmeter's design allows for accurate potential measurement without significantly disrupting the circuit's function. Overall, a solid grasp of potential difference and circuit dynamics is essential for comprehending the voltmeter's role in experiments.
chewchun
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In set-up with two half-cells and a voltmeter, the potential difference is measured using the voltmeter.
But voltmeter has high resistance,which i know is still able to measure potential difference,but wouldn't it prevent electrons from flowing
What i meant was,the use of voltmeter creates a 'open circuit' which prevents electron flow and hence reaction in the two half cell will not take place?
But my teacher says that reaction takes place in both half cell,which meant that there is electron transfer and redox??
Does this have to do with some physics regarding voltmeter??
 
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Voltmeter closes the circuit, it doesn't leave the circuit open. What voltmeter does it measures the current flowing through a known resistance, then it displays the result as potential (V=RI).

Actually it is not a chemistry question, but physics question - how does the voltmeter work and what happens in the circuit with a voltmeter (doesn't matter if it is a battery powered circuit or some other kind).
 
Borek said:
Voltmeter closes the circuit, it doesn't leave the circuit open. What voltmeter does it measures the current flowing through a known resistance, then it displays the result as potential (V=RI).

Actually it is not a chemistry question, but physics question - how does the voltmeter work and what happens in the circuit with a voltmeter (doesn't matter if it is a battery powered circuit or some other kind).
So the high resistance of voltmeter must play a role.what if there is no voltmeter,for instance just a strip wire...is experiment the same?
Btw wouldn't the high resistance prevent current from flowing or something like that??
 
Please read how voltmeter works and how it measures the potential difference, your questions are directly answered by the theory behind it. Most likely any general physics book will do.

You can't understand potential measurement without good understanding what a potential difference is and how it is related to the charge, and what happens when you close the circuit - that's all physics.
 
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